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• Analyzed: May 12, 2026, 4:04 AM
• Findings: 1
• Version: 1.0.0
• Hash: e3c2d287c400f44cd5f92e2fa1c5724d076913a56e1034fcb1baa281e5f3c8fe
• Source: palm
• External report: View on VirusTotal

Findings (1)

``` ```python def solve(): # Read input: N, M, K N, M, K = map(int, input().split()) # Read input: N lines of M characters grid = [] for _ in range(N): grid.append(input()) # Initialize a 2D DP array: dp[r][c] stores the maximum length of a valid path ending at (r, c) # A valid path means the characters encountered so far form a prefix of the target string. # The target string is implicitly defined by the problem: it's a string of K identical characters. # For example, if K=3, the target string could be "AAA", "BBB", etc. # Since we are looking for a path of K identical characters, we need to store not just the length, # but also the character that forms the path. # So, dp[r][c] will be a dictionary where keys are characters ('A'-'Z') and values are the # maximum length of a path ending at (r, c) using that character. # dp[r][c][char] = max_length dp = [[{} for _ in range(M)] for _ in range(N)] # Base cases: For each cell (r, c), a path of length 1 can end there using the character at grid[r][c]. for r in range(N